C program that print sum of all integers divisible by 2 between given two numbers - My CS Tutorial

In this tutorial we will learn how to write a program that find and print sum of all integers divisible by 2 between given two numbers.

Explanation:-

1. We initialized
   • i---->to use in for loop.
   • num1-->to store 1st number.
   • num2-->to store 2nd number.
   • sum---->to store the sum of all integers that are divisible by 2.
2. We took the number 1 and 2 from user.(let us take num1=1 and num2 =10)
3. Now we enter the loop where i=num1-->1 and i<=num2-->10.
   • Loop 1:
     • i=1 and as i<=10 the loop executes
     • then as i%2 (i.e. 1%2) is 1 so the if statement won't execute keeping sum =0
     • Now the value of i is incremented by 1.Therefore,i=2.
   • Loop 2 now i = 2
     • i=2 and as i<=10 the loop executes
     • then as i%2 (i.e. 2%2) is 0 so the if statement will execute.
     • As sum+=i(i.e. same as sum=sum+i). Therefore,sum=0+2=2.
     • Now the value of i is incremented by 1.Therefore,i=3.
   • Loop 3 now i=3
     • i=3 and as i<=10 the loop executes
     • then as i%2 (i.e. 1%2) is 1 so the if statement wont execute keeping sum =2
     • Now the value of i is incremented by 1.Therefore,i=4.
   • Loop 4 now i=4
     • i=4 and as i<=10 the loop executes
     • then as i%2 (i.e. 4%2) is 0 so the if statement will execute.
     • As sum+=i(i.e. same as sum=sum+i).Therefore,sum=2+4=6.
     • Now the value of i is incremented by 1.Therefore,i=5.
   • This continues till i becomes 10 where
   • When i=5 , i%2=>5%2=1 which is not 0 so sum remains same which is 6.
   • When i=6,sum=6+6=12
   • When i=7, if statement will not execute so sum remains 10.
   • When i=8, sum=12+8=20
   • When i=9,sum remains same as 20.
   • When i=10 ,sum=20+10=30.
   • In this way it will execute till i=10 after that as i becomes 11 the loop terminates.
   • Then the value in sum is printed which is 30 in this case.

C program code

#include<stdio.h>

#include<conio.h>

void main()

{

 int i,sum=0,num1,num2;

 printf("\n Enter Number1\n ");

 scanf("%d",&num1);

 printf("\n Enter Number2\n ");

 scanf("%d",&num2);

 printf("\n the numbers are=");

 for(i=num1;i<=num2;i++)

 {

   if(i%2==0)

   {

     sum+=i;

     printf("\n %d",i);

    }

 }

 printf("\n The sum of all integers divisible by 2

       between %d and %d is %d\n",num1,num2,sum);

getch();

}

OUTPUT 1:

OUTPUT 2:

In first output,the value of first number is 1
And the value of second number is 15

After calculation

The sum of all integers divisible by 2 between these two numbers are 56

And that numbers are

2, 4, 6, 8, 10, 12, 14

In second output,the value of first number is 5

And the value of second number is 25

After calculation

The sum of all integers divisible by 2 between these two numbers are 150

And that numbers are

6, 8, 10, 12, 14, 16, 18, 20,  22, 24

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Created by-- HARSH CHAUHAN