C program to check whether given number is Armstrong or not - My CS Tutorial

In this tutorial, we will learn how to write a program that check given number is Armstrong or not.

C Program Code

#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
  int num,x,j,temp,sum=0;;
  printf("\n Enter a number to know it is armstrong or not:\n ");
  scanf("%d",&num);
  temp=num;
  while(num>0)
  {
    x=num%10;
    sum+=x*x*x;
    num=num/10;
  }
  if(sum==temp)
  {
    printf("\n Given number %d is an armstrong number.\n",temp);
  }
  else
  {
    printf("\n Given number %d is not an armstrong number.\n",temp);
  }
  getch();
}

OUTPUT 1:

OUTPUT 2:

In first output, enter value of number is 153

Given number is Armstrong.


In second output, enter value of number is 258

Given number is not Armstrong.

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Created by-- HARSH CHAUHAN