C Program to Make a Simple Calculator Using switch...case - My CS Tutorial

In this tutorial,we will learn how write a program that solve +,-,*,/ operations.In this post we will make a calculator that solve arithmetic operations.This is a C program to create a simple calculator using switch and break statement.

Explanation:-

The program starts with initializing

choice → For storing the operators as +,-,/,*

num1,num2 → For storing two integers

result → For storing the resulting value

flag → To store true or false.

First we take choice of user (+,-,/,*) then the two numbers.

Now we use switch case

If the user enters '+' as his choice then the result will be result=num1+num2

If the user enters '-' as his choice then the result will be result=num1-num2

If the user enters '/' as his choice then the result will be result=num1/num2

if num2 is not zero else flag will be zero and the output would be undefined

If the user enters '*' as his choice then the result will be result=num1*num2

C program code

#include<stdio.h>
#include<conio.h>
void main()
{
char choice;
float num1,num2,result;
int flag=1;
printf("\n Enter +,-,/,* for knowing the result: ");
scanf("%c",&choice);
printf("\n Enter first number: ");
scanf("%f",&num1);
printf("\n Enter second number: ");
scanf("%f",&num2);

switch(choice)
{
case '+':
result=num1+num2;
break;
case '-':
result=num1-num2;
break;
case '/':
{

if(num2==0)
{
flag=0;
}
else
{
result=num1/num2;
}
break;
}
case '*': result=num1*num2;
break;
default:printf("Error");
break;
}
if(flag==1)
{
printf("\n %f %c %f = %f",num1,choice,num2,result);
}
else
{
printf("%f %c %f = undefined\n",num1,choice,num2);
}
getch();
}

OUTPUT 1:

OUTPUT 2:

In first output,the operation is ( + ) and the value of input first and second number is 45 and 50
After operation
The value is 95

45 + 50 = 95

In second output,the operation is ( / ) and the value of input first and second number is 55 and 10
After operation
The value is 5.5

55 / 10 =5.5



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Created by-- HARSH CHAUHAN