C program to print sum of series 1^2- 2^2+ 3^2- 4^2+ 5^2-...........n^2 - My CS Tutorial

In this tutorial we will learn how to write a c program to print sum of series 1^2- 2^2+ 3^2- 4^2+ 5^2-..........+n^2.

C program code

#include <stdio.h>

#include<conio.h>

 #include<math.h>

 void main()

 {

   int a,num,sum=0;

   printf("\n Enter number:\n ");

   scanf("%d",&num);

   for(a=1;a<=num;a++)

   {

    if(a%2==0)

    {

     sum-=pow(a,2);

     }

     if(a%2==1)

     {

      sum+=pow(a,2);

     }

   }

   printf("\n Sum of series:\n ");

   for(a=1;a<=num;a++)

   {

    if(a!=num)

    {

     if(a%2==0)

     {

         printf("%d^2+ ",a);

      }

      else

      {

       printf("%d^2- ",a);

      }

     }

     else

     {

      printf("%d^2 = %d\n",a,sum);

     }

   }

   getch();

 }

OUTPUT:

In this output the value of input number is 8

 Sum of series:
 1^2- 2^2+ 3^2- 4^2+ 5^2- 6^2+ 7^2- 8^2

And the sum of series is -36

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Created by-- HARSH CHAUHAN