In this tutorial we will learn how to write a program that check given number is perfect or not.
In this output the value of input number is 28
Given number 28 is a perfect number because its divisors sum is equal to 28
C program code
#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
int num,a,sum=0;
printf("\n Enter a number to know whether it is perfect or not:\n ");
scanf("%d",&num);
for(a=1;a<num;a++)
{
if(num%a==0)
{
sum+=a;
}
}
if(sum==num)
{
printf("\n The given number %d is perfect.\n ",num);
}
else
{
printf("\n The given number %d is not perfect because the sum of its divisors are %d\n",num,sum);
}
getch();
}
OUTPUT:
In this output the value of input number is 28
Given number 28 is a perfect number because its divisors sum is equal to 28
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Created by-- HARSH CHAUHAN
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